Base | Representation |
---|---|
bin | 11101010010110001011… |
… | …001110010101110001001 |
3 | 21010102221220012100201101 |
4 | 131102301121302232021 |
5 | 230440131340214423 |
6 | 4140434042421401 |
7 | 265302352242412 |
oct | 35226131625611 |
9 | 7112856170641 |
10 | 2013021023113 |
11 | 706798985211 |
12 | 286178801861 |
13 | 117a9a0b7089 |
14 | 6d605d2c809 |
15 | 3756b1d37ad |
hex | 1d4b1672b89 |
2013021023113 has 2 divisors, whose sum is σ = 2013021023114. Its totient is φ = 2013021023112.
The previous prime is 2013021023107. The next prime is 2013021023149. The reversal of 2013021023113 is 3113201203102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1573097909824 + 439923113289 = 1254232^2 + 663267^2 .
It is a cyclic number.
It is not a de Polignac number, because 2013021023113 - 217 = 2013020892041 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013021023173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006510511556 + 1006510511557.
It is an arithmetic number, because the mean of its divisors is an integer number (1006510511557).
Almost surely, 22013021023113 is an apocalyptic number.
It is an amenable number.
2013021023113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013021023113 is an equidigital number, since it uses as much as digits as its factorization.
2013021023113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2013021023113 its reverse (3113201203102), we get a palindrome (5126222226215).
The spelling of 2013021023113 in words is "two trillion, thirteen billion, twenty-one million, twenty-three thousand, one hundred thirteen".
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