Base | Representation |
---|---|
bin | 1001001001110111011111… |
… | …10111010110001011000101 |
3 | 2122021102200002220110011112 |
4 | 10210323233313112023011 |
5 | 10114303213144344141 |
6 | 110451412143014405 |
7 | 4145235065246231 |
oct | 444735767261305 |
9 | 78242602813145 |
10 | 20130241012421 |
11 | 6461207291391 |
12 | 2311460b9a405 |
13 | b303730a2167 |
14 | 4d84477435c1 |
15 | 24d978e557eb |
hex | 124eefdd62c5 |
20130241012421 has 4 divisors (see below), whose sum is σ = 20130560668992. Its totient is φ = 20129921355852.
The previous prime is 20130241012391. The next prime is 20130241012429. The reversal of 20130241012421 is 12421014203102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20130241012421 - 214 = 20130240996037 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20130241012429) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159733805 + ... + 159859778.
It is an arithmetic number, because the mean of its divisors is an integer number (5032640167248).
Almost surely, 220130241012421 is an apocalyptic number.
It is an amenable number.
20130241012421 is a deficient number, since it is larger than the sum of its proper divisors (319656571).
20130241012421 is an equidigital number, since it uses as much as digits as its factorization.
20130241012421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319656570.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 20130241012421 its reverse (12421014203102), we get a palindrome (32551255215523).
The spelling of 20130241012421 in words is "twenty trillion, one hundred thirty billion, two hundred forty-one million, twelve thousand, four hundred twenty-one".
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