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2013030113113 = 4264947199937
BaseRepresentation
bin11101010010110001111…
…100011101111101011001
321010102222112022011212001
4131102301330131331121
5230440141202104423
64140435005321001
7265302522432025
oct35226174357531
97112875264761
102013030113113
117067a3023708
1228617b866161
13117a9bc4a686
146d607217385
153756bdcbcad
hex1d4b1f1df59

2013030113113 has 4 divisors (see below), whose sum is σ = 2013077355700. Its totient is φ = 2012982870528.

The previous prime is 2013030113069. The next prime is 2013030113117. The reversal of 2013030113113 is 3113110303102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1138034503369 + 874995609744 = 1066787^2 + 935412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013030113113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013030113117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23557320 + ... + 23642617.

It is an arithmetic number, because the mean of its divisors is an integer number (503269338925).

Almost surely, 22013030113113 is an apocalyptic number.

It is an amenable number.

2013030113113 is a deficient number, since it is larger than the sum of its proper divisors (47242587).

2013030113113 is an equidigital number, since it uses as much as digits as its factorization.

2013030113113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47242586.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2013030113113 its reverse (3113110303102), we get a palindrome (5126140416215).

The spelling of 2013030113113 in words is "two trillion, thirteen billion, thirty million, one hundred thirteen thousand, one hundred thirteen".

Divisors: 1 42649 47199937 2013030113113