2013030113117 has 2 divisors, whose sum is σ = 2013030113118. Its totient is φ = 2013030113116.

The previous prime is 2013030113069. The next prime is 2013030113161. The reversal of 2013030113117 is 7113110303102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1271168306521 + 741861806596 = 1127461^2 + 861314^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013030113117 - 2¹² = 2013030109021 is a prime.

It is a super-3 number, since 3×2013030113117³ (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013030113092 and 2013030113101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013030113417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006515056558 + 1006515056559.

It is an arithmetic number, because the mean of its divisors is an integer number (1006515056559).

Almost surely, 2^{2013030113117} is an apocalyptic number.

It is an amenable number.

2013030113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013030113117 is an equidigital number, since it uses as much as digits as its factorization.

2013030113117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

Adding to 2013030113117 its reverse (7113110303102), we get a palindrome (9126140416219).

The spelling of 2013030113117 in words is "two trillion, thirteen billion, thirty million, one hundred thirteen thousand, one hundred seventeen".