2013040020111 has 4 divisors (see below), whose sum is σ = 2684053360152. Its totient is φ = 1342026680072.

The previous prime is 2013040020107. The next prime is 2013040020139. The reversal of 2013040020111 is 1110200403102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013040020111 - 2² = 2013040020107 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013040020181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335506670016 + ... + 335506670021.

It is an arithmetic number, because the mean of its divisors is an integer number (671013340038).

Almost surely, 2^{2013040020111} is an apocalyptic number.

2013040020111 is a deficient number, since it is larger than the sum of its proper divisors (671013340041).

2013040020111 is an equidigital number, since it uses as much as digits as its factorization.

2013040020111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671013340040.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 2013040020111 its reverse (1110200403102), we get a palindrome (3123240423213).

The spelling of 2013040020111 in words is "two trillion, thirteen billion, forty million, twenty thousand, one hundred eleven".