20130403331213 has 4 divisors (see below), whose sum is σ = 23006175235680. Its totient is φ = 17254631426748.

The previous prime is 20130403331209. The next prime is 20130403331231. The reversal of 20130403331213 is 31213330403102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20130403331213 - 2² = 20130403331209 is a prime.

It is a super-2 number, since 2×20130403331213² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130403331243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1437885952223 + ... + 1437885952236.

It is an arithmetic number, because the mean of its divisors is an integer number (5751543808920).

Almost surely, 2^{20130403331213} is an apocalyptic number.

It is an amenable number.

20130403331213 is a deficient number, since it is larger than the sum of its proper divisors (2875771904467).

20130403331213 is an equidigital number, since it uses as much as digits as its factorization.

20130403331213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2875771904466.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 20130403331213 its reverse (31213330403102), we get a palindrome (51343733734315).

The spelling of 20130403331213 in words is "twenty trillion, one hundred thirty billion, four hundred three million, three hundred thirty-one thousand, two hundred thirteen".