Base | Representation |
---|---|
bin | 11101010010110010101… |
… | …110011001000010001101 |
3 | 21010110000102221001212210 |
4 | 131102302232121002031 |
5 | 230440203024401031 |
6 | 4140440154021033 |
7 | 265303041606441 |
oct | 35226256310215 |
9 | 7113012831783 |
10 | 2013043200141 |
11 | 7067aa452136 |
12 | 286184117779 |
13 | 117aa188038c |
14 | 6d608c62821 |
15 | 3756d114746 |
hex | 1d4b2b9908d |
2013043200141 has 8 divisors (see below), whose sum is σ = 2692166536864. Its totient is φ = 1337974331760.
The previous prime is 2013043200101. The next prime is 2013043200151. The reversal of 2013043200141 is 1410023403102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-2013043200141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013043200101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1013615926 + ... + 1013617911.
It is an arithmetic number, because the mean of its divisors is an integer number (336520817108).
Almost surely, 22013043200141 is an apocalyptic number.
It is an amenable number.
2013043200141 is a deficient number, since it is larger than the sum of its proper divisors (679123336723).
2013043200141 is a wasteful number, since it uses less digits than its factorization.
2013043200141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2027234171.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 2013043200141 its reverse (1410023403102), we get a palindrome (3423066603243).
The spelling of 2013043200141 in words is "two trillion, thirteen billion, forty-three million, two hundred thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •