Search a number
-
+
20131001341 = 111830091031
BaseRepresentation
bin10010101111111001…
…101011001111111101
31220221222000211022021
4102233321223033331
5312212014020331
613125325120141
71311602455003
oct225771531775
956858024267
1020131001341
1185a04752a0
123a999b9051
131b8a884119
14d8d866a73
157cc4e6211
hex4afe6b3fd

20131001341 has 4 divisors (see below), whose sum is σ = 21961092384. Its totient is φ = 18300910300.

The previous prime is 20131001287. The next prime is 20131001347. The reversal of 20131001341 is 14310013102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20131001341 - 27 = 20131001213 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131001347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915045505 + ... + 915045526.

It is an arithmetic number, because the mean of its divisors is an integer number (5490273096).

Almost surely, 220131001341 is an apocalyptic number.

It is an amenable number.

20131001341 is a deficient number, since it is larger than the sum of its proper divisors (1830091043).

20131001341 is a wasteful number, since it uses less digits than its factorization.

20131001341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1830091042.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 20131001341 its reverse (14310013102), we get a palindrome (34441014443).

The spelling of 20131001341 in words is "twenty billion, one hundred thirty-one million, one thousand, three hundred forty-one".

Divisors: 1 11 1830091031 20131001341