20131011013103 has 4 divisors (see below), whose sum is σ = 20131021584240. Its totient is φ = 20131000441968.

The previous prime is 20131011013049. The next prime is 20131011013159. The reversal of 20131011013103 is 30131011013102.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20131011013103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131011018103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1548158 + ... + 6531371.

It is an arithmetic number, because the mean of its divisors is an integer number (5032755396060).

Almost surely, 2^{20131011013103} is an apocalyptic number.

20131011013103 is a deficient number, since it is larger than the sum of its proper divisors (10571137).

20131011013103 is an equidigital number, since it uses as much as digits as its factorization.

20131011013103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10571136.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 20131011013103 its reverse (30131011013102), we get a palindrome (50262022026205).

Subtracting 20131011013103 from its reverse (30131011013102), we obtain a palindrome (9999999999999).

The spelling of 20131011013103 in words is "twenty trillion, one hundred thirty-one billion, eleven million, thirteen thousand, one hundred three".