Base | Representation |
---|---|
bin | 10010101111111001… |
… | …110010011111011011 |
3 | 1220221222002022222212 |
4 | 102233321302133123 |
5 | 312212020443003 |
6 | 13125325505335 |
7 | 1311602640326 |
oct | 225771623733 |
9 | 56858068885 |
10 | 20131031003 |
11 | 85a0495606 |
12 | 3a99a1224b |
13 | 1b8a894785 |
14 | d8d8737bd |
15 | 7cc4eedd8 |
hex | 4afe727db |
20131031003 has 4 divisors (see below), whose sum is σ = 20675112960. Its totient is φ = 19586949048.
The previous prime is 20131030999. The next prime is 20131031017. The reversal of 20131031003 is 30013013102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30013013102 = 2 ⋅15006506551.
It is a cyclic number.
It is not a de Polignac number, because 20131031003 - 22 = 20131030999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20131031033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272040923 + ... + 272040996.
It is an arithmetic number, because the mean of its divisors is an integer number (5168778240).
Almost surely, 220131031003 is an apocalyptic number.
20131031003 is a deficient number, since it is larger than the sum of its proper divisors (544081957).
20131031003 is an equidigital number, since it uses as much as digits as its factorization.
20131031003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 544081956.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 20131031003 its reverse (30013013102), we get a palindrome (50144044105).
The spelling of 20131031003 in words is "twenty billion, one hundred thirty-one million, thirty-one thousand, three".
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