2013103334041 has 4 divisors (see below), whose sum is σ = 2013182178084. Its totient is φ = 2013024490000.

The previous prime is 2013103334027. The next prime is 2013103334051. The reversal of 2013103334041 is 1404333013102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1283609691225 + 729493642816 = 1132965^2 + 854104^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2013103334041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013103333997 and 2013103334015.

It is not an unprimeable number, because it can be changed into a prime (2013103334051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39383710 + ... + 39434791.

It is an arithmetic number, because the mean of its divisors is an integer number (503295544521).

Almost surely, 2^{2013103334041} is an apocalyptic number.

It is an amenable number.

2013103334041 is a deficient number, since it is larger than the sum of its proper divisors (78844043).

2013103334041 is an equidigital number, since it uses as much as digits as its factorization.

2013103334041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78844042.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 2013103334041 its reverse (1404333013102), we get a palindrome (3417436347143).

The spelling of 2013103334041 in words is "two trillion, thirteen billion, one hundred three million, three hundred thirty-four thousand, forty-one".