Base | Representation |
---|---|
bin | 1001001001111000111110… |
… | …00110101001000100101001 |
3 | 2122021111201100012120220121 |
4 | 10210330133012221010221 |
5 | 10114311324042114040 |
6 | 110452022533523241 |
7 | 4145263530565606 |
oct | 444743706510451 |
9 | 78244640176817 |
10 | 20131033551145 |
11 | 6461583696470 |
12 | 23116424a3521 |
13 | b3046b341b9a |
14 | 4d84c0ac96ad |
15 | 24d9c3806c4a |
hex | 124f1f1a9129 |
20131033551145 has 16 divisors (see below), whose sum is σ = 27903550249728. Its totient is φ = 13779530986240.
The previous prime is 20131033551137. The next prime is 20131033551163. The reversal of 20131033551145 is 54115533013102.
It is not a de Polignac number, because 20131033551145 - 23 = 20131033551137 is a prime.
It is a super-2 number, since 2×201310335511452 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20131033551145.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10765257649 + ... + 10765259518.
It is an arithmetic number, because the mean of its divisors is an integer number (1743971890608).
Almost surely, 220131033551145 is an apocalyptic number.
It is an amenable number.
20131033551145 is a deficient number, since it is larger than the sum of its proper divisors (7772516698583).
20131033551145 is a wasteful number, since it uses less digits than its factorization.
20131033551145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21530517200.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 20131033551145 its reverse (54115533013102), we get a palindrome (74246566564247).
The spelling of 20131033551145 in words is "twenty trillion, one hundred thirty-one billion, thirty-three million, five hundred fifty-one thousand, one hundred forty-five".
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