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20131052303 = 47981419563
BaseRepresentation
bin10010101111111001…
…110111101100001111
31220221222010102012202
4102233321313230033
5312212022133203
613125330152115
71311603056405
oct225771675417
956858112182
1020131052303
1185a04aa60a
123a99a2263b
131b8a8a138b
14d8d87b475
157cc506388
hex4afe77b0f

20131052303 has 4 divisors (see below), whose sum is σ = 20131519848. Its totient is φ = 20130584760.

The previous prime is 20131052257. The next prime is 20131052323. The reversal of 20131052303 is 30325013102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20131052303 - 214 = 20131035919 is a prime.

It is a super-2 number, since 2×201310523032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131052323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161801 + ... + 257762.

It is an arithmetic number, because the mean of its divisors is an integer number (5032879962).

Almost surely, 220131052303 is an apocalyptic number.

20131052303 is a deficient number, since it is larger than the sum of its proper divisors (467545).

20131052303 is an equidigital number, since it uses as much as digits as its factorization.

20131052303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 467544.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 20131052303 its reverse (30325013102), we get a palindrome (50456065405).

The spelling of 20131052303 in words is "twenty billion, one hundred thirty-one million, fifty-two thousand, three hundred three".

Divisors: 1 47981 419563 20131052303