Base | Representation |
---|---|
bin | 1011101101111100001… |
… | …0110010011010000101 |
3 | 201020121200022022000011 |
4 | 2323133002302122011 |
5 | 11244240444424131 |
6 | 232251503350221 |
7 | 20354443255330 |
oct | 2733702623205 |
9 | 636550268004 |
10 | 201310545541 |
11 | 78414611496 |
12 | 330225b2371 |
13 | 15ca29aa101 |
14 | 9a5a189617 |
15 | 53835490b1 |
hex | 2edf0b2685 |
201310545541 has 4 divisors (see below), whose sum is σ = 230069194912. Its totient is φ = 172551896172.
The previous prime is 201310545539. The next prime is 201310545581. The reversal of 201310545541 is 145545013102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 201310545541 - 21 = 201310545539 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201310545581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14379324675 + ... + 14379324688.
It is an arithmetic number, because the mean of its divisors is an integer number (57517298728).
Almost surely, 2201310545541 is an apocalyptic number.
It is an amenable number.
201310545541 is a deficient number, since it is larger than the sum of its proper divisors (28758649371).
201310545541 is an equidigital number, since it uses as much as digits as its factorization.
201310545541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28758649370.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 201310545541 its reverse (145545013102), we get a palindrome (346855558643).
The spelling of 201310545541 in words is "two hundred one billion, three hundred ten million, five hundred forty-five thousand, five hundred forty-one".
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