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20131100311 = 729324414021
BaseRepresentation
bin10010101111111010…
…000011011010010111
31220221222012212001211
4102233322003122113
5312212030202221
613125331202251
71311603346360
oct225772033227
956858185054
1020131100311
1185a0532693
123a99a46387
131b8a8ba19a
14d8d890b67
157cc5156e1
hex4afe83697

20131100311 has 16 divisors (see below), whose sum is σ = 23100694848. Its totient is φ = 17185017600.

The previous prime is 20131100309. The next prime is 20131100347. The reversal of 20131100311 is 11300113102.

It is a cyclic number.

It is not a de Polignac number, because 20131100311 - 21 = 20131100309 is a prime.

It is a super-2 number, since 2×201311003112 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20131100291 and 20131100300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131100351) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5004481 + ... + 5008501.

It is an arithmetic number, because the mean of its divisors is an integer number (1443793428).

Almost surely, 220131100311 is an apocalyptic number.

20131100311 is a deficient number, since it is larger than the sum of its proper divisors (2969594537).

20131100311 is a wasteful number, since it uses less digits than its factorization.

20131100311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6762.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 20131100311 its reverse (11300113102), we get a palindrome (31431213413).

The spelling of 20131100311 in words is "twenty billion, one hundred thirty-one million, one hundred thousand, three hundred eleven".

Divisors: 1 7 293 2051 2441 4021 17087 28147 715213 1178153 5006491 8247071 9815261 68706827 2875871473 20131100311