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2013110112003 = 31637409918573
BaseRepresentation
bin11101010010110110101…
…101101000111100000011
321010110012002211112200220
4131102312231220330003
5230440322142041003
64140450544114123
7265304513421654
oct35226655507403
97113162745626
102013110112003
117068341a3aa1
122861a2605943
13117ab26aa3b3
146d613abd52b
1537573e30353
hex1d4b6b68f03

2013110112003 has 8 divisors (see below), whose sum is σ = 2685786496848. Its totient is φ = 1341253567584.

The previous prime is 2013110111989. The next prime is 2013110112031. The reversal of 2013110112003 is 3002110113102.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2013110112003 - 218 = 2013109849859 is a prime.

It is a super-2 number, since 2×20131101120032 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2013110152003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 204954376 + ... + 204964197.

It is an arithmetic number, because the mean of its divisors is an integer number (335723312106).

Almost surely, 22013110112003 is an apocalyptic number.

2013110112003 is a deficient number, since it is larger than the sum of its proper divisors (672676384845).

2013110112003 is a wasteful number, since it uses less digits than its factorization.

2013110112003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 409920213.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 2013110112003 its reverse (3002110113102), we get a palindrome (5015220225105).

The spelling of 2013110112003 in words is "two trillion, thirteen billion, one hundred ten million, one hundred twelve thousand, three".

Divisors: 1 3 1637 4911 409918573 1229755719 671036704001 2013110112003