Base | Representation |
---|---|
bin | 111011111111101… |
… | …1001111101100011 |
3 | 12012022000120220220 |
4 | 1313333121331203 |
5 | 13110324010430 |
6 | 531431534123 |
7 | 100613103462 |
oct | 16777317543 |
9 | 5168016826 |
10 | 2013110115 |
11 | 943391475 |
12 | 48222a343 |
13 | 2610b7723 |
14 | 15150c9d9 |
15 | bbb02110 |
hex | 77fd9f63 |
2013110115 has 8 divisors (see below), whose sum is σ = 3220976208. Its totient is φ = 1073658720.
The previous prime is 2013110111. The next prime is 2013110129. The reversal of 2013110115 is 5110113102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2013110115 - 22 = 2013110111 is a prime.
It is a super-2 number, since 2×20131101152 = 8105224670230626450, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15), and also a Moran number because the ratio is a prime number: 134207341 = 2013110115 / (2 + 0 + 1 + 3 + 1 + 1 + 0 + 1 + 1 + 5).
It is a junction number, because it is equal to n+sod(n) for n = 2013110094 and 2013110103.
It is not an unprimeable number, because it can be changed into a prime (2013110111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67103656 + ... + 67103685.
It is an arithmetic number, because the mean of its divisors is an integer number (402622026).
Almost surely, 22013110115 is an apocalyptic number.
2013110115 is a deficient number, since it is larger than the sum of its proper divisors (1207866093).
2013110115 is a wasteful number, since it uses less digits than its factorization.
2013110115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134207349.
The product of its (nonzero) digits is 30, while the sum is 15.
The square root of 2013110115 is about 44867.6956729449. The cubic root of 2013110115 is about 1262.6680080957.
Adding to 2013110115 its reverse (5110113102), we get a palindrome (7123223217).
The spelling of 2013110115 in words is "two billion, thirteen million, one hundred ten thousand, one hundred fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •