Base | Representation |
---|---|
bin | 111011111111101… |
… | …1001111110111011 |
3 | 12012022000121001011 |
4 | 1313333121332323 |
5 | 13110324011303 |
6 | 531431534351 |
7 | 100613103646 |
oct | 16777317673 |
9 | 5168017034 |
10 | 2013110203 |
11 | 943391545 |
12 | 48222a3b7 |
13 | 2610b7790 |
14 | 15150ca5d |
15 | bbb0216d |
hex | 77fd9fbb |
2013110203 has 4 divisors (see below), whose sum is σ = 2167964848. Its totient is φ = 1858255560.
The previous prime is 2013110191. The next prime is 2013110237. The reversal of 2013110203 is 3020113102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3020113102 = 2 ⋅1510056551.
It is a cyclic number.
It is not a de Polignac number, because 2013110203 - 29 = 2013109691 is a prime.
It is a super-2 number, since 2×20131102032 = 8105225378845402418, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 154854631 = 2013110203 / (2 + 0 + 1 + 3 + 1 + 1 + 0 + 2 + 0 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013110263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77427303 + ... + 77427328.
It is an arithmetic number, because the mean of its divisors is an integer number (541991212).
Almost surely, 22013110203 is an apocalyptic number.
2013110203 is a deficient number, since it is larger than the sum of its proper divisors (154854645).
2013110203 is a wasteful number, since it uses less digits than its factorization.
2013110203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154854644.
The product of its (nonzero) digits is 36, while the sum is 13.
The square root of 2013110203 is about 44867.6966536059. The cubic root of 2013110203 is about 1262.6680264943.
Adding to 2013110203 its reverse (3020113102), we get a palindrome (5033223305).
The spelling of 2013110203 in words is "two billion, thirteen million, one hundred ten thousand, two hundred three".
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