Base | Representation |
---|---|
bin | 11101010010110110101… |
… | …110001001001010101100 |
3 | 21010110012010002020210010 |
4 | 131102312232021022230 |
5 | 230440322210302022 |
6 | 4140450551013220 |
7 | 265304514511560 |
oct | 35226656111254 |
9 | 7113163066703 |
10 | 2013110244012 |
11 | 70683428419a |
12 | 2861a266a210 |
13 | 117ab27254ca |
14 | 6d613b156a0 |
15 | 37573e5950c |
hex | 1d4b6b892ac |
2013110244012 has 48 divisors (see below), whose sum is σ = 5391736367360. Its totient is φ = 572662671552.
The previous prime is 2013110244007. The next prime is 2013110244023. The reversal of 2013110244012 is 2104420113102.
It is a super-2 number, since 2×20131102440122 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 2013110244012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52307398 + ... + 52345869.
Almost surely, 22013110244012 is an apocalyptic number.
It is an amenable number.
2013110244012 is an abundant number, since it is smaller than the sum of its proper divisors (3378626123348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013110244012 is a wasteful number, since it uses less digits than its factorization.
2013110244012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104653510 (or 104653508 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 2013110244012 its reverse (2104420113102), we get a palindrome (4117530357114).
The spelling of 2013110244012 in words is "two trillion, thirteen billion, one hundred ten million, two hundred forty-four thousand, twelve".
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