Search a number
-
+
2013113103 = 3691971111
BaseRepresentation
bin111011111111101…
…1010101100001111
312012022000202000120
41313333122230033
513110324104403
6531432000023
7100613115261
oct16777325417
95168022016
102013113103
11943393741
12482230013
132610b8bb1
1415150db31
15bbb02e53
hex77fdab0f

2013113103 has 8 divisors (see below), whose sum is σ = 2688038016. Its totient is φ = 1340131800.

The previous prime is 2013113093. The next prime is 2013113107. The reversal of 2013113103 is 3013113102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2013113103 - 225 = 1979558671 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013113107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 483483 + ... + 487628.

It is an arithmetic number, because the mean of its divisors is an integer number (336004752).

Almost surely, 22013113103 is an apocalyptic number.

2013113103 is a deficient number, since it is larger than the sum of its proper divisors (674924913).

2013113103 is an equidigital number, since it uses as much as digits as its factorization.

2013113103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 971805.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 2013113103 is about 44867.7289708316. The cubic root of 2013113103 is about 1262.6686328091.

Adding to 2013113103 its reverse (3013113102), we get a palindrome (5026226205).

Subtracting 2013113103 from its reverse (3013113102), we obtain a palindrome (999999999).

The spelling of 2013113103 in words is "two billion, thirteen million, one hundred thirteen thousand, one hundred three".

Divisors: 1 3 691 2073 971111 2913333 671037701 2013113103