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2013113104075 = 52412431952441
BaseRepresentation
bin11101010010110110111…
…001000011011011001011
321010110012022110120001101
4131102312321003123023
5230440323423312300
64140451132202231
7265304551023133
oct35226671033313
97113168416041
102013113104075
11706835957a87
122861a3609377
13117ab31b7258
146d61425bac3
1537574321b6a
hex1d4b6e436cb

2013113104075 has 12 divisors (see below), whose sum is σ = 2496322053288. Its totient is φ = 1610450609600.

The previous prime is 2013113104049. The next prime is 2013113104091. The reversal of 2013113104075 is 5704013113102.

It is not a de Polignac number, because 2013113104075 - 213 = 2013113095883 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 54855 + ... + 2007295.

It is an arithmetic number, because the mean of its divisors is an integer number (208026837774).

Almost surely, 22013113104075 is an apocalyptic number.

2013113104075 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

2013113104075 is a deficient number, since it is larger than the sum of its proper divisors (483208949213).

2013113104075 is a wasteful number, since it uses less digits than its factorization.

2013113104075 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1993694 (or 1993689 counting only the distinct ones).

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 2013113104075 its reverse (5704013113102), we get a palindrome (7717126217177).

The spelling of 2013113104075 in words is "two trillion, thirteen billion, one hundred thirteen million, one hundred four thousand, seventy-five".

Divisors: 1 5 25 41243 206215 1031075 1952441 9762205 48811025 80524524163 402622620815 2013113104075