Base | Representation |
---|---|
bin | 11101010010110110111… |
… | …001000011011011001011 |
3 | 21010110012022110120001101 |
4 | 131102312321003123023 |
5 | 230440323423312300 |
6 | 4140451132202231 |
7 | 265304551023133 |
oct | 35226671033313 |
9 | 7113168416041 |
10 | 2013113104075 |
11 | 706835957a87 |
12 | 2861a3609377 |
13 | 117ab31b7258 |
14 | 6d61425bac3 |
15 | 37574321b6a |
hex | 1d4b6e436cb |
2013113104075 has 12 divisors (see below), whose sum is σ = 2496322053288. Its totient is φ = 1610450609600.
The previous prime is 2013113104049. The next prime is 2013113104091. The reversal of 2013113104075 is 5704013113102.
It is not a de Polignac number, because 2013113104075 - 213 = 2013113095883 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 54855 + ... + 2007295.
It is an arithmetic number, because the mean of its divisors is an integer number (208026837774).
Almost surely, 22013113104075 is an apocalyptic number.
2013113104075 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2013113104075 is a deficient number, since it is larger than the sum of its proper divisors (483208949213).
2013113104075 is a wasteful number, since it uses less digits than its factorization.
2013113104075 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1993694 (or 1993689 counting only the distinct ones).
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 2013113104075 its reverse (5704013113102), we get a palindrome (7717126217177).
The spelling of 2013113104075 in words is "two trillion, thirteen billion, one hundred thirteen million, one hundred four thousand, seventy-five".
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