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20131142345 = 54026228469
BaseRepresentation
bin10010101111111010…
…001101101011001001
31220221222021222201122
4102233322031223021
5312212033023340
613125332125025
71311603613046
oct225772155311
956858258648
1020131142345
1185a0561226
123a99a66775
131b8a903362
14d8d8a21cd
157cc522db5
hex4afe8dac9

20131142345 has 4 divisors (see below), whose sum is σ = 24157370820. Its totient is φ = 16104913872.

The previous prime is 20131142327. The next prime is 20131142401. The reversal of 20131142345 is 54324113102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3101153344 + 17029989001 = 55688^2 + 130499^2 .

It is a cyclic number.

It is not a de Polignac number, because 20131142345 - 28 = 20131142089 is a prime.

It is a super-2 number, since 2×201311423452 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2013114230 + ... + 2013114239.

It is an arithmetic number, because the mean of its divisors is an integer number (6039342705).

Almost surely, 220131142345 is an apocalyptic number.

It is an amenable number.

20131142345 is a deficient number, since it is larger than the sum of its proper divisors (4026228475).

20131142345 is an equidigital number, since it uses as much as digits as its factorization.

20131142345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4026228474.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 20131142345 its reverse (54324113102), we get a palindrome (74455255447).

The spelling of 20131142345 in words is "twenty billion, one hundred thirty-one million, one hundred forty-two thousand, three hundred forty-five".

Divisors: 1 5 4026228469 20131142345