201311686113103 has 4 divisors (see below), whose sum is σ = 201311754359728. Its totient is φ = 201311617866480.

The previous prime is 201311686113079. The next prime is 201311686113107. The reversal of 201311686113103 is 301311686113102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201311686113103 - 2⁴¹ = 199112662857551 is a prime.

It is a super-2 number, since 2×201311686113103² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201311686113107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29488851 + ... + 35668132.

It is an arithmetic number, because the mean of its divisors is an integer number (50327938589932).

Almost surely, 2^{201311686113103} is an apocalyptic number.

201311686113103 is a deficient number, since it is larger than the sum of its proper divisors (68246625).

201311686113103 is an equidigital number, since it uses as much as digits as its factorization.

201311686113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68246624.

The product of its (nonzero) digits is 15552, while the sum is 37.

Subtracting 201311686113103 from its reverse (301311686113102), we obtain a palindrome (99999999999999).

The spelling of 201311686113103 in words is "two hundred one trillion, three hundred eleven billion, six hundred eighty-six million, one hundred thirteen thousand, one hundred three".