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2013117 = 3671039
BaseRepresentation
bin111101011011110111101
310210021110220
413223132331
51003404432
6111051553
723053101
oct7533675
93707426
102013117
111155537
12810bb9
135563c2
143a5901
1529b72c
hex1eb7bd

2013117 has 4 divisors (see below), whose sum is σ = 2684160. Its totient is φ = 1342076.

The previous prime is 2013113. The next prime is 2013119. The reversal of 2013117 is 7113102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013117 - 22 = 2013113 is a prime.

It is an Ulam number.

It is a D-number.

It is a junction number, because it is equal to n+sod(n) for n = 2013096 and 2013105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335517 + ... + 335522.

It is an arithmetic number, because the mean of its divisors is an integer number (671040).

22013117 is an apocalyptic number.

It is an amenable number.

2013117 is a deficient number, since it is larger than the sum of its proper divisors (671043).

2013117 is an equidigital number, since it uses as much as digits as its factorization.

2013117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671042.

The product of its (nonzero) digits is 42, while the sum is 15.

The square root of 2013117 is about 1418.8435431717. The cubic root of 2013117 is about 126.2669447570.

Subtracting from 2013117 its sum of digits (15), we obtain a palindrome (2013102).

Adding to 2013117 its reverse (7113102), we get a palindrome (9126219).

The spelling of 2013117 in words is "two million, thirteen thousand, one hundred seventeen".

Divisors: 1 3 671039 2013117