201312020213 has 4 divisors (see below), whose sum is σ = 210064716768. Its totient is φ = 192559323660.

The previous prime is 201312020183. The next prime is 201312020243. The reversal of 201312020213 is 312020213102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (201312020183) and next prime (201312020243).

It is a cyclic number.

It is not a de Polignac number, because 201312020213 - 2¹⁶ = 201311954677 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201312020191 and 201312020200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201312020243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4376348243 + ... + 4376348288.

It is an arithmetic number, because the mean of its divisors is an integer number (52516179192).

Almost surely, 2^201312020213 is an apocalyptic number.

201312020213 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

201312020213 is a deficient number, since it is larger than the sum of its proper divisors (8752696555).

201312020213 is an equidigital number, since it uses as much as digits as its factorization.

201312020213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8752696554.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 201312020213 its reverse (312020213102), we get a palindrome (513332233315).

The spelling of 201312020213 in words is "two hundred one billion, three hundred twelve million, twenty thousand, two hundred thirteen".