Base | Representation |
---|---|
bin | 1001001001111001010011… |
… | …01000111011001001001101 |
3 | 2122021112011122210212210001 |
4 | 10210330221220323021031 |
5 | 10114312204314411341 |
6 | 110452052250244301 |
7 | 4145301105165313 |
oct | 444745150731115 |
9 | 78245148725701 |
10 | 20131210310221 |
11 | 646166444514a |
12 | 2311691726691 |
13 | b30498b4c85a |
14 | 4d84da37c0b3 |
15 | 24d9d40bed31 |
hex | 124f29a3b24d |
20131210310221 has 4 divisors (see below), whose sum is σ = 20131738463200. Its totient is φ = 20130682157244.
The previous prime is 20131210310191. The next prime is 20131210310273. The reversal of 20131210310221 is 12201301213102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20131210310221 - 239 = 19581454496333 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20131210319221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264019311 + ... + 264095548.
It is an arithmetic number, because the mean of its divisors is an integer number (5032934615800).
Almost surely, 220131210310221 is an apocalyptic number.
It is an amenable number.
20131210310221 is a deficient number, since it is larger than the sum of its proper divisors (528152979).
20131210310221 is an equidigital number, since it uses as much as digits as its factorization.
20131210310221 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 528152978.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 20131210310221 its reverse (12201301213102), we get a palindrome (32332511523323).
The spelling of 20131210310221 in words is "twenty trillion, one hundred thirty-one billion, two hundred ten million, three hundred ten thousand, two hundred twenty-one".
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