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2013121200001 = 9672081821303
BaseRepresentation
bin11101010010110111010…
…111111011111110000001
321010110012212200212120111
4131102313113323332001
5230440333011400001
64140452021511321
7265305006602332
oct35226727737601
97113185625514
102013121200001
1170683a48762a
122861a6272541
13117ab4a90242
146d615368289
1537574dc0851
hex1d4b75fbf81

2013121200001 has 4 divisors (see below), whose sum is σ = 2015203022272. Its totient is φ = 2011039377732.

The previous prime is 2013121199963. The next prime is 2013121200043. The reversal of 2013121200001 is 1000021213102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013121200001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013121203001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1040909685 + ... + 1040911618.

It is an arithmetic number, because the mean of its divisors is an integer number (503800755568).

Almost surely, 22013121200001 is an apocalyptic number.

It is an amenable number.

2013121200001 is a deficient number, since it is larger than the sum of its proper divisors (2081822271).

2013121200001 is an equidigital number, since it uses as much as digits as its factorization.

2013121200001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2081822270.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 2013121200001 its reverse (1000021213102), we get a palindrome (3013142413103).

It can be divided in two parts, 2013121 and 200001, that added together give a palindrome (2213122).

The spelling of 2013121200001 in words is "two trillion, thirteen billion, one hundred twenty-one million, two hundred thousand, one".

Divisors: 1 967 2081821303 2013121200001