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2013121210143 = 35911373566159
BaseRepresentation
bin11101010010110111010…
…111111110011100011111
321010110012212201101111010
4131102313113332130133
5230440333012211033
64140452022030303
7265305006644031
oct35226727763437
97113185641433
102013121210143
1170683a49420a
122861a6278393
13117ab4a94a44
146d61536bc51
1537574dc3863
hex1d4b75fe71f

2013121210143 has 8 divisors (see below), whose sum is σ = 2729655878400. Its totient is φ = 1319333674328.

The previous prime is 2013121210117. The next prime is 2013121210171. The reversal of 2013121210143 is 3410121213102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2013121210143 - 213 = 2013121201951 is a prime.

It is a super-3 number, since 3×20131212101433 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013121210193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5686782903 + ... + 5686783256.

It is an arithmetic number, because the mean of its divisors is an integer number (341206984800).

Almost surely, 22013121210143 is an apocalyptic number.

2013121210143 is a deficient number, since it is larger than the sum of its proper divisors (716534668257).

2013121210143 is a wasteful number, since it uses less digits than its factorization.

2013121210143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11373566221.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 2013121210143 its reverse (3410121213102), we get a palindrome (5423242423245).

The spelling of 2013121210143 in words is "two trillion, thirteen billion, one hundred twenty-one million, two hundred ten thousand, one hundred forty-three".

Divisors: 1 3 59 177 11373566159 34120698477 671040403381 2013121210143