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201312123000000 = 26356232917567
BaseRepresentation
bin101101110001011110100001…
…100101001001010011000000
3222101210020202222112201102120
4231301132201211021103000
5202341244211442000000
61552053302415044240
760255215034640425
oct5561364145112300
9871706688481376
10201312123000000
1159164aa0267901
121a6b377a810680
138843861b553ac
14379d7b7287d4c
1518418cc42e6a0
hexb717a19494c0

201312123000000 has 392 divisors, whose sum is σ = 694736987252736. Its totient is φ = 51349161600000.

The previous prime is 201312122999909. The next prime is 201312123000017. The reversal of 201312123000000 is 321213102.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 67541217 + ... + 70458783.

Almost surely, 2201312123000000 is an apocalyptic number.

201312123000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 201312123000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (347368493626368).

201312123000000 is an abundant number, since it is smaller than the sum of its proper divisors (493424864252736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201312123000000 is an frugal number, since it uses more digits than its factorization.

201312123000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2917635 (or 2917600 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 201312123000000 its reverse (321213102), we get a palindrome (201312444213102).

The spelling of 201312123000000 in words is "two hundred one trillion, three hundred twelve billion, one hundred twenty-three million", and thus it is an aban number.