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2013122131323 = 3671040710441
BaseRepresentation
bin11101010010110111011…
…011011111010101111011
321010110012221110012002220
4131102313123133111323
5230440333231200243
64140452053455123
7265305020531502
oct35226733372573
97113187405086
102013122131323
1170683aa63316
122861a66414a3
13117ab5028114
146d61552b839
1537575006783
hex1d4b76df57b

2013122131323 has 4 divisors (see below), whose sum is σ = 2684162841768. Its totient is φ = 1342081420880.

The previous prime is 2013122131313. The next prime is 2013122131343. The reversal of 2013122131323 is 3231312213102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013122131323 - 28 = 2013122131067 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2013122131293 and 2013122131302.

It is not an unprimeable number, because it can be changed into a prime (2013122131313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335520355218 + ... + 335520355223.

It is an arithmetic number, because the mean of its divisors is an integer number (671040710442).

Almost surely, 22013122131323 is an apocalyptic number.

2013122131323 is a deficient number, since it is larger than the sum of its proper divisors (671040710445).

2013122131323 is an equidigital number, since it uses as much as digits as its factorization.

2013122131323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671040710444.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 2013122131323 its reverse (3231312213102), we get a palindrome (5244434344425).

The spelling of 2013122131323 in words is "two trillion, thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, three hundred twenty-three".

Divisors: 1 3 671040710441 2013122131323