Base | Representation |
---|---|
bin | 1001001001111001011111… |
… | …00101100110001001101111 |
3 | 2122021112102121120210010122 |
4 | 10210330233211212021233 |
5 | 10114312410341213403 |
6 | 110452110213155155 |
7 | 4145303426326655 |
oct | 444745745461157 |
9 | 78245377523118 |
10 | 20131310101103 |
11 | 6461705803553 |
12 | 23116bb02babb |
13 | b304b371c106 |
14 | 4d8509716dd5 |
15 | 24d9dcc32838 |
hex | 124f2f96626f |
20131310101103 has 4 divisors (see below), whose sum is σ = 20131323114768. Its totient is φ = 20131297087440.
The previous prime is 20131310101033. The next prime is 20131310101153. The reversal of 20131310101103 is 30110101313102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20131310101103 - 210 = 20131310100079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20131310101153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3815318 + ... + 7404003.
It is an arithmetic number, because the mean of its divisors is an integer number (5032830778692).
Almost surely, 220131310101103 is an apocalyptic number.
20131310101103 is a deficient number, since it is larger than the sum of its proper divisors (13013665).
20131310101103 is a wasteful number, since it uses less digits than its factorization.
20131310101103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13013664.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 20131310101103 its reverse (30110101313102), we get a palindrome (50241411414205).
The spelling of 20131310101103 in words is "twenty trillion, one hundred thirty-one billion, three hundred ten million, one hundred one thousand, one hundred three".
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