2013131100301 has 4 divisors (see below), whose sum is σ = 2013133963104. Its totient is φ = 2013128237500.

The previous prime is 2013131100283. The next prime is 2013131100373. The reversal of 2013131100301 is 1030011313102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2013131100301 - 2⁷ = 2013131100173 is a prime.

It is a super-2 number, since 2×2013131100301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013131100391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 431976 + ... + 2052526.

It is an arithmetic number, because the mean of its divisors is an integer number (503283490776).

Almost surely, 2^{2013131100301} is an apocalyptic number.

It is an amenable number.

2013131100301 is a deficient number, since it is larger than the sum of its proper divisors (2862803).

2013131100301 is a wasteful number, since it uses less digits than its factorization.

2013131100301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2862802.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 2013131100301 its reverse (1030011313102), we get a palindrome (3043142413403).

The spelling of 2013131100301 in words is "two trillion, thirteen billion, one hundred thirty-one million, one hundred thousand, three hundred one".