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2013131114 = 21006565557
BaseRepresentation
bin111011111111101…
…1111000101101010
312012022001122201122
41313333133011222
513110330143424
6531432215242
7100613221631
oct16777370552
95168048648
102013131114
119433a6225
1248223a522
132610c4157
14151516518
15bbb0845e
hex77fdf16a

2013131114 has 4 divisors (see below), whose sum is σ = 3019696674. Its totient is φ = 1006565556.

The previous prime is 2013131033. The next prime is 2013131117. The reversal of 2013131114 is 4111313102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1050084025 + 963047089 = 32405^2 + 31033^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2013131092 and 2013131101.

It is not an unprimeable number, because it can be changed into a prime (2013131117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503282777 + ... + 503282780.

Almost surely, 22013131114 is an apocalyptic number.

2013131114 is a deficient number, since it is larger than the sum of its proper divisors (1006565560).

2013131114 is a wasteful number, since it uses less digits than its factorization.

2013131114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1006565559.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 2013131114 is about 44867.9296825695. The cubic root of 2013131114 is about 1262.6723984291.

Adding to 2013131114 its reverse (4111313102), we get a palindrome (6124444216).

The spelling of 2013131114 in words is "two billion, thirteen million, one hundred thirty-one thousand, one hundred fourteen".

Divisors: 1 2 1006565557 2013131114