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2013131201223 = 3671043733741
BaseRepresentation
bin11101010010110111111…
…110000101101011000111
321010110020120111222200010
4131102313332011223013
5230440343041414343
64140453020121303
7265305160605402
oct35226776055307
97113216458603
102013131201223
117068450986aa
122861a9696233
13117ab6b8251c
146d61680cd39
1537575be8d33
hex1d4b7f85ac7

2013131201223 has 4 divisors (see below), whose sum is σ = 2684174934968. Its totient is φ = 1342087467480.

The previous prime is 2013131201219. The next prime is 2013131201243. The reversal of 2013131201223 is 3221021313102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2013131201223 - 22 = 2013131201219 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2013131201223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013131201243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335521866868 + ... + 335521866873.

It is an arithmetic number, because the mean of its divisors is an integer number (671043733742).

Almost surely, 22013131201223 is an apocalyptic number.

2013131201223 is a deficient number, since it is larger than the sum of its proper divisors (671043733745).

2013131201223 is an equidigital number, since it uses as much as digits as its factorization.

2013131201223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671043733744.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2013131201223 its reverse (3221021313102), we get a palindrome (5234152514325).

The spelling of 2013131201223 in words is "two trillion, thirteen billion, one hundred thirty-one million, two hundred one thousand, two hundred twenty-three".

Divisors: 1 3 671043733741 2013131201223