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20131312100130 = 232571137923933203
BaseRepresentation
bin1001001001111001011111…
…01101001110001100100010
32122021112102202100100021200
410210330233231032030202
510114312411344201010
6110452110324102030
74145303452324020
oct444745755161442
978245382310250
1020131312100130
116461706949440
1223116bb834916
13b304b3c6bc7a
144d8509ab7710
1524d9dcec9cc0
hex124f2fb4e322

20131312100130 has 384 divisors, whose sum is σ = 65476784056320. Its totient is φ = 4169047034880.

The previous prime is 20131312100113. The next prime is 20131312100167. The reversal of 20131312100130 is 3100121313102.

20131312100130 is a `hidden beast` number, since 201 + 313 + 1 + 21 + 0 + 0 + 130 = 666.

It is a super-2 number, since 2×201313121001302 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 6285141109 + ... + 6285144311.

It is an arithmetic number, because the mean of its divisors is an integer number (170512458480).

Almost surely, 220131312100130 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20131312100130, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32738392028160).

20131312100130 is an abundant number, since it is smaller than the sum of its proper divisors (45345471956190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20131312100130 is a wasteful number, since it uses less digits than its factorization.

20131312100130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6006 (or 6003 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 20131312100130 its reverse (3100121313102), we get a palindrome (23231433413232).

The spelling of 20131312100130 in words is "twenty trillion, one hundred thirty-one billion, three hundred twelve million, one hundred thousand, one hundred thirty".