Base | Representation |
---|---|
bin | 11101010010111000000… |
… | …001001001000000101000 |
3 | 21010110020122000122012100 |
4 | 131102320001021000220 |
5 | 230440343243020240 |
6 | 4140453045213400 |
7 | 265305200450136 |
oct | 35227001110050 |
9 | 7113218018170 |
10 | 2013132001320 |
11 | 706845594840 |
12 | 2861a9a01260 |
13 | 117ab70a275b |
14 | 6d61697a756 |
15 | 37575d05e30 |
hex | 1d4b8049028 |
2013132001320 has 384 divisors, whose sum is σ = 7315711603200. Its totient is φ = 475858022400.
The previous prime is 2013132001301. The next prime is 2013132001339. The reversal of 2013132001320 is 231002313102.
2013132001320 is a `hidden beast` number, since 20 + 1 + 3 + 1 + 320 + 0 + 1 + 320 = 666.
It is an interprime number because it is at equal distance from previous prime (2013132001301) and next prime (2013132001339).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 2013132001293 and 2013132001302.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 542767626 + ... + 542771334.
It is an arithmetic number, because the mean of its divisors is an integer number (19051332300).
Almost surely, 22013132001320 is an apocalyptic number.
2013132001320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2013132001320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3657855801600).
2013132001320 is an abundant number, since it is smaller than the sum of its proper divisors (5302579601880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2013132001320 is a wasteful number, since it uses less digits than its factorization.
2013132001320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7121 (or 7114 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 2013132001320 its reverse (231002313102), we get a palindrome (2244134314422).
The spelling of 2013132001320 in words is "two trillion, thirteen billion, one hundred thirty-two million, one thousand, three hundred twenty".
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