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2013133101301 = 7287590443043
BaseRepresentation
bin11101010010111000000…
…101010101100011110101
321010110020201002112002101
4131102320011111203311
5230440344033220201
64140453124542101
7265305213011110
oct35227005254365
97113221075071
102013133101301
11706846176213
122861aa251931
13117ab739932a
146d616b85577
1537575e71d01
hex1d4b81558f5

2013133101301 has 4 divisors (see below), whose sum is σ = 2300723544352. Its totient is φ = 1725542658252.

The previous prime is 2013133101299. The next prime is 2013133101311. The reversal of 2013133101301 is 1031013313102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2013133101301 - 21 = 2013133101299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013133101311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143795221515 + ... + 143795221528.

It is an arithmetic number, because the mean of its divisors is an integer number (575180886088).

Almost surely, 22013133101301 is an apocalyptic number.

It is an amenable number.

2013133101301 is a deficient number, since it is larger than the sum of its proper divisors (287590443051).

2013133101301 is an equidigital number, since it uses as much as digits as its factorization.

2013133101301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287590443050.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 2013133101301 its reverse (1031013313102), we get a palindrome (3044146414403).

The spelling of 2013133101301 in words is "two trillion, thirteen billion, one hundred thirty-three million, one hundred one thousand, three hundred one".

Divisors: 1 7 287590443043 2013133101301