201313332311233 has 4 divisors (see below), whose sum is σ = 201910701250180. Its totient is φ = 200715963372288.

The previous prime is 201313332311191. The next prime is 201313332311261. The reversal of 201313332311233 is 332113233313102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 24316171286449 + 176997161024784 = 4931143^2 + 13304028^2 .

It is a cyclic number.

It is not a de Polignac number, because 201313332311233 - 2²¹ = 201313330214081 is a prime.

It is a super-2 number, since 2×201313332311233² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201313332311195 and 201313332311204.

It is not an unprimeable number, because it can be changed into a prime (201313332311033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298684468968 + ... + 298684469641.

It is an arithmetic number, because the mean of its divisors is an integer number (50477675312545).

Almost surely, 2^{201313332311233} is an apocalyptic number.

It is an amenable number.

201313332311233 is a deficient number, since it is larger than the sum of its proper divisors (597368938947).

201313332311233 is an equidigital number, since it uses as much as digits as its factorization.

201313332311233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 597368938946.

The product of its (nonzero) digits is 17496, while the sum is 31.

Adding to 201313332311233 its reverse (332113233313102), we get a palindrome (533426565624335).

The spelling of 201313332311233 in words is "two hundred one trillion, three hundred thirteen billion, three hundred thirty-two million, three hundred eleven thousand, two hundred thirty-three".