Base | Representation |
---|---|
bin | 1001001001111001100011… |
… | …01000001000101101111011 |
3 | 2122021112111222222100120011 |
4 | 10210330301220020231323 |
5 | 10114312443121241103 |
6 | 110452113434442351 |
7 | 4145304323233420 |
oct | 444746150105573 |
9 | 78245458870504 |
10 | 20131344321403 |
11 | 6461723056797 |
12 | 231170a5933b7 |
13 | b304ba841003 |
14 | 4d85100a3d47 |
15 | 24d9e0c41d6d |
hex | 124f31a08b7b |
20131344321403 has 64 divisors (see below), whose sum is σ = 24671288678400. Its totient is φ = 16081935851520.
The previous prime is 20131344321317. The next prime is 20131344321437. The reversal of 20131344321403 is 30412344313102.
It is not a de Polignac number, because 20131344321403 - 221 = 20131342224251 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20131344321443) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3083370043 + ... + 3083376571.
It is an arithmetic number, because the mean of its divisors is an integer number (385488885600).
Almost surely, 220131344321403 is an apocalyptic number.
20131344321403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
20131344321403 is a deficient number, since it is larger than the sum of its proper divisors (4539944356997).
20131344321403 is an frugal number, since it uses more digits than its factorization.
20131344321403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7529 (or 7483 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 20131344321403 its reverse (30412344313102), we get a palindrome (50543688634505).
The spelling of 20131344321403 in words is "twenty trillion, one hundred thirty-one billion, three hundred forty-four million, three hundred twenty-one thousand, four hundred three".
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