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201314023301 = 404431497771
BaseRepresentation
bin1011101101111101000…
…0000011011110000101
3201020121220211222121002
42323133100003132011
511244242342221201
6232252110103045
720354514651506
oct2733720033605
9636556758532
10201314023301
1178416577376
12330237aaa85
1315ca3627061
149a5a812bad
1553839d476b
hex2edf403785

201314023301 has 4 divisors (see below), whose sum is σ = 201314925504. Its totient is φ = 201313121100.

The previous prime is 201314023217. The next prime is 201314023319. The reversal of 201314023301 is 103320413102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201314023301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201314023381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155546 + ... + 653316.

It is an arithmetic number, because the mean of its divisors is an integer number (50328731376).

Almost surely, 2201314023301 is an apocalyptic number.

It is an amenable number.

201314023301 is a deficient number, since it is larger than the sum of its proper divisors (902203).

201314023301 is an equidigital number, since it uses as much as digits as its factorization.

201314023301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 902202.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 201314023301 its reverse (103320413102), we get a palindrome (304634436403).

The spelling of 201314023301 in words is "two hundred one billion, three hundred fourteen million, twenty-three thousand, three hundred one".

Divisors: 1 404431 497771 201314023301