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20131420123 = 43468172561
BaseRepresentation
bin10010101111111011…
…010001011111011011
31220221222211002202201
4102233323101133123
5312212120420443
613125342111031
71311606150643
oct225773213733
956858732681
1020131420123
1185a07309a1
123a99b7b477
131b8a99c919
14d8d935523
157cc57a34d
hex4afed17db

20131420123 has 4 divisors (see below), whose sum is σ = 20599592728. Its totient is φ = 19663247520.

The previous prime is 20131420081. The next prime is 20131420147. The reversal of 20131420123 is 32102413102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20131420123 - 213 = 20131411931 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20131420123.

It is not an unprimeable number, because it can be changed into a prime (20131420163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234086238 + ... + 234086323.

It is an arithmetic number, because the mean of its divisors is an integer number (5149898182).

Almost surely, 220131420123 is an apocalyptic number.

20131420123 is a deficient number, since it is larger than the sum of its proper divisors (468172605).

20131420123 is an equidigital number, since it uses as much as digits as its factorization.

20131420123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 468172604.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 20131420123 its reverse (32102413102), we get a palindrome (52233833225).

The spelling of 20131420123 in words is "twenty billion, one hundred thirty-one million, four hundred twenty thousand, one hundred twenty-three".

Divisors: 1 43 468172561 20131420123