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2013143121221 = 6528730835283
BaseRepresentation
bin11101010010111000101…
…011100011110101000101
321010110021101221120211112
4131102320223203311011
5230440404114334341
64140454123414405
7265305364122521
oct35227053436505
97113241846745
102013143121221
1170685089a341
122861b1684405
13117ab9496c8b
146d618232d81
1537576ca0aeb
hex1d4b8ae3d45

2013143121221 has 4 divisors (see below), whose sum is σ = 2013174021792. Its totient is φ = 2013112220652.

The previous prime is 2013143121203. The next prime is 2013143121247. The reversal of 2013143121221 is 1221213413102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013143121221 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013143121721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15352355 + ... + 15482928.

It is an arithmetic number, because the mean of its divisors is an integer number (503293505448).

Almost surely, 22013143121221 is an apocalyptic number.

It is an amenable number.

2013143121221 is a deficient number, since it is larger than the sum of its proper divisors (30900571).

2013143121221 is an equidigital number, since it uses as much as digits as its factorization.

2013143121221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30900570.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2013143121221 its reverse (1221213413102), we get a palindrome (3234356534323).

The spelling of 2013143121221 in words is "two trillion, thirteen billion, one hundred forty-three million, one hundred twenty-one thousand, two hundred twenty-one".

Divisors: 1 65287 30835283 2013143121221