Search a number
-
+
2013200102023 = 111825710024549
BaseRepresentation
bin11101010010111100000…
…100111011001010000111
321010110102101011111210121
4131102330010323022013
5230441013211231043
64140503521002411
7265306655343355
oct35227404731207
97113371144717
102013200102023
1170687aa78910
12286208783407
13117ac8227926
146d621a267d5
153757bca8ded
hex1d4bc13b287

2013200102023 has 8 divisors (see below), whose sum is σ = 2196338806800. Its totient is φ = 1830081482880.

The previous prime is 2013200101961. The next prime is 2013200102029. The reversal of 2013200102023 is 3202010023102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013200102023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013200101988 and 2013200102006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013200102029) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4811448 + ... + 5213101.

It is an arithmetic number, because the mean of its divisors is an integer number (274542350850).

Almost surely, 22013200102023 is an apocalyptic number.

2013200102023 is a deficient number, since it is larger than the sum of its proper divisors (183138704777).

2013200102023 is a wasteful number, since it uses less digits than its factorization.

2013200102023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10042817.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 2013200102023 its reverse (3202010023102), we get a palindrome (5215210125125).

The spelling of 2013200102023 in words is "two trillion, thirteen billion, two hundred million, one hundred two thousand, twenty-three".

Divisors: 1 11 18257 200827 10024549 110270039 183018191093 2013200102023