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201320111231 = 1371469489863
BaseRepresentation
bin1011101101111110011…
…1010001110001111111
3201020122100022021122222
42323133213101301333
511244300422024411
6232252444355555
720354620465541
oct2733747216177
9636570267588
10201320111231
1178419a55318
1233025845bbb
1315ca4979095
149a5b559691
1553842d84db
hex2edf9d1c7f

201320111231 has 4 divisors (see below), whose sum is σ = 202789601232. Its totient is φ = 199850621232.

The previous prime is 201320111207. The next prime is 201320111243. The reversal of 201320111231 is 132111023102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201320111231 - 222 = 201315916927 is a prime.

It is a super-2 number, since 2×2013201112312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201320111131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 734744795 + ... + 734745068.

It is an arithmetic number, because the mean of its divisors is an integer number (50697400308).

Almost surely, 2201320111231 is an apocalyptic number.

201320111231 is a deficient number, since it is larger than the sum of its proper divisors (1469490001).

201320111231 is a wasteful number, since it uses less digits than its factorization.

201320111231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1469490000.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 201320111231 its reverse (132111023102), we get a palindrome (333431134333).

The spelling of 201320111231 in words is "two hundred one billion, three hundred twenty million, one hundred eleven thousand, two hundred thirty-one".

Divisors: 1 137 1469489863 201320111231