Search a number
-
+
2013201553403 = 12689158657227
BaseRepresentation
bin11101010010111100001…
…010011101011111111011
321010110102110220020201102
4131102330022131133323
5230441014044202103
64140504012042015
7265310003566655
oct35227412353773
97113373806642
102013201553403
1170688087a2a7
1228620916330b
13117ac8615431
146d621cc36d5
153757be93e88
hex1d4bc29d7fb

2013201553403 has 4 divisors (see below), whose sum is σ = 2013360223320. Its totient is φ = 2013042883488.

The previous prime is 2013201553399. The next prime is 2013201553471. The reversal of 2013201553403 is 3043551023102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013201553403 - 22 = 2013201553399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013201553603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79315925 + ... + 79341302.

It is an arithmetic number, because the mean of its divisors is an integer number (503340055830).

Almost surely, 22013201553403 is an apocalyptic number.

2013201553403 is a deficient number, since it is larger than the sum of its proper divisors (158669917).

2013201553403 is a wasteful number, since it uses less digits than its factorization.

2013201553403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158669916.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 2013201553403 its reverse (3043551023102), we get a palindrome (5056752576505).

The spelling of 2013201553403 in words is "two trillion, thirteen billion, two hundred one million, five hundred fifty-three thousand, four hundred three".

Divisors: 1 12689 158657227 2013201553403