Base | Representation |
---|---|
bin | 11101010010111100010… |
… | …000000100010010011011 |
3 | 21010110102120122220122001 |
4 | 131102330100010102123 |
5 | 230441014433214003 |
6 | 4140504103341431 |
7 | 265310022230344 |
oct | 35227420042233 |
9 | 7113376586561 |
10 | 2013203023003 |
11 | 706881693447 |
12 | 286209751877 |
13 | 117ac8a0b313 |
14 | 6d6221870cb |
15 | 3757c18461d |
hex | 1d4bc40449b |
2013203023003 has 4 divisors (see below), whose sum is σ = 2013207866280. Its totient is φ = 2013198179728.
The previous prime is 2013203022973. The next prime is 2013203023021. The reversal of 2013203023003 is 3003203023102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013203023003 - 225 = 2013169468571 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013203023043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1732825 + ... + 2651242.
It is an arithmetic number, because the mean of its divisors is an integer number (503301966570).
Almost surely, 22013203023003 is an apocalyptic number.
2013203023003 is a deficient number, since it is larger than the sum of its proper divisors (4843277).
2013203023003 is an equidigital number, since it uses as much as digits as its factorization.
2013203023003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4843276.
The product of its (nonzero) digits is 648, while the sum is 19.
Adding to 2013203023003 its reverse (3003203023102), we get a palindrome (5016406046105).
Subtracting 2013203023003 from its reverse (3003203023102), we obtain a palindrome (990000000099).
The spelling of 2013203023003 in words is "two trillion, thirteen billion, two hundred three million, twenty-three thousand, three".
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