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201321100335 = 3513421406689
BaseRepresentation
bin1011101101111110101…
…1000011010000101111
3201020122102011112110110
42323133223003100233
511244301200202320
6232252521511103
720354632055325
oct2733753032057
9636572145413
10201321100335
117841a570463
1233026042493
1315ca4c34354
149a5b735d15
1553844315e0
hex2edfac342f

201321100335 has 8 divisors (see below), whose sum is σ = 322113760560. Its totient is φ = 107371253504.

The previous prime is 201321100289. The next prime is 201321100367. The reversal of 201321100335 is 533001123102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201321100335 - 212 = 201321096239 is a prime.

It is a super-2 number, since 2×2013211003352 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6710703330 + ... + 6710703359.

It is an arithmetic number, because the mean of its divisors is an integer number (40264220070).

Almost surely, 2201321100335 is an apocalyptic number.

201321100335 is a deficient number, since it is larger than the sum of its proper divisors (120792660225).

201321100335 is a wasteful number, since it uses less digits than its factorization.

201321100335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13421406697.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 201321100335 its reverse (533001123102), we get a palindrome (734322223437).

The spelling of 201321100335 in words is "two hundred one billion, three hundred twenty-one million, one hundred thousand, three hundred thirty-five".

Divisors: 1 3 5 15 13421406689 40264220067 67107033445 201321100335