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201321123103 = 2005110040453
BaseRepresentation
bin1011101101111110101…
…1001000110100011111
3201020122102012200200201
42323133223020310133
511244301201414403
6232252522204331
720354632211602
oct2733753106437
9636572180621
10201321123103
117841a586581
12330260536a7
1315ca4c41819
149a5b740339
15538443821d
hex2edfac8d1f

201321123103 has 4 divisors (see below), whose sum is σ = 201331183608. Its totient is φ = 201311062600.

The previous prime is 201321123089. The next prime is 201321123109. The reversal of 201321123103 is 301321123102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201321123103 - 217 = 201320992031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201321123109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000176 + ... + 5040277.

It is an arithmetic number, because the mean of its divisors is an integer number (50332795902).

Almost surely, 2201321123103 is an apocalyptic number.

201321123103 is a deficient number, since it is larger than the sum of its proper divisors (10060505).

201321123103 is a wasteful number, since it uses less digits than its factorization.

201321123103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10060504.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 201321123103 its reverse (301321123102), we get a palindrome (502642246205).

Subtracting 201321123103 from its reverse (301321123102), we obtain a palindrome (99999999999).

The spelling of 201321123103 in words is "two hundred one billion, three hundred twenty-one million, one hundred twenty-three thousand, one hundred three".

Divisors: 1 20051 10040453 201321123103