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2013212001311 = 7287601714473
BaseRepresentation
bin11101010010111100110…
…010010100010000011111
321010110110012120001112222
4131102330302110100133
5230441024233020221
64140505024015555
7265310161443230
oct35227462242037
97113405501488
102013212001311
11706886765a35
122862107615bb
13117aca832b24
146d623443087
153757cd599ab
hex1d4bcc9441f

2013212001311 has 4 divisors (see below), whose sum is σ = 2300813715792. Its totient is φ = 1725610286832.

The previous prime is 2013212001221. The next prime is 2013212001337. The reversal of 2013212001311 is 1131002123102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013212001311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2013212001311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013212001371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143800857230 + ... + 143800857243.

It is an arithmetic number, because the mean of its divisors is an integer number (575203428948).

Almost surely, 22013212001311 is an apocalyptic number.

2013212001311 is a deficient number, since it is larger than the sum of its proper divisors (287601714481).

2013212001311 is an equidigital number, since it uses as much as digits as its factorization.

2013212001311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 287601714480.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 2013212001311 its reverse (1131002123102), we get a palindrome (3144214124413).

The spelling of 2013212001311 in words is "two trillion, thirteen billion, two hundred twelve million, one thousand, three hundred eleven".

Divisors: 1 7 287601714473 2013212001311