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20132211022003 = 53379853038151
BaseRepresentation
bin1001001001111011001010…
…10010010101100010110011
32122021121202101211022021101
410210331211102111202303
510114321232010201003
6110452335435105231
74145334646122343
oct444754522254263
978247671738241
1020132211022003
116462028304783
1223119108a2217
13b305c82789c2
144d8593232d23
1524da41d9211d
hex124f654958b3

20132211022003 has 4 divisors (see below), whose sum is σ = 20512064060208. Its totient is φ = 19752357983800.

The previous prime is 20132211021971. The next prime is 20132211022019. The reversal of 20132211022003 is 30022011223102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20132211022003 - 25 = 20132211021971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20132211082003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189926519023 + ... + 189926519128.

It is an arithmetic number, because the mean of its divisors is an integer number (5128016015052).

Almost surely, 220132211022003 is an apocalyptic number.

20132211022003 is a deficient number, since it is larger than the sum of its proper divisors (379853038205).

20132211022003 is an equidigital number, since it uses as much as digits as its factorization.

20132211022003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379853038204.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 20132211022003 its reverse (30022011223102), we get a palindrome (50154222245105).

The spelling of 20132211022003 in words is "twenty trillion, one hundred thirty-two billion, two hundred eleven million, twenty-two thousand, three".

Divisors: 1 53 379853038151 20132211022003